Question: Take a look into the attached video and answer the following question below!  Propane (C3H8) burns in this reaction: C3H8+5O2→4H2O+3CO2 If 12 g of propane is burned, how many grams and molecules of CO2 is produced?
2 People tried to answer this question

 26.4 gram CO2, 3.6132e23 molecules
 33.64 gram CO2, 3.877e23 molecules
 35.64 gram CO2, 4.877e23 molecules
 2.64 gram CO2, 1.2132e23 molecules

Excellent :)

Carbon (C) has 12.00 grams per mole.

Hydrogen (H) has 1.00 grams per mole.

Oxygen (O) has 16.00 grams per mole.

One molecule of Propane contains 3 carbon atoms and 8 hydrogen atoms.

Step 1: Mw (C3H8)= (3x12.00+8x1.00) gr/mole= 44 gr/mole

n=m/mw : Step 2:  12 gr C3H8 is equal to 0.27 mole C3H8.

Step 3:  Since there is a ratio of 3:1 CO2 to C3H8, for every 0.2 mole C3H8 there are 0.81 mole CO2 .

Step 3: Convert 0.81 mole CO2 to gram CO2.

n=m/mw :

Mw (CO2)=(12.00+2x16.00)=44 gr/mole.

0.81 mole CO2 is equal to 35.64 gram CO2.

Molecules of CO2: (0.81 mole)x(6.022e23 molecules/mole)=4.877e23 molecules

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